Program to Add Two Times (in minutes - seconds ) using C++ Structures
#include <iostream>
using namespace std;
struct TotalTime{
int min;
float sec;
}t1 , t2, sum;
int main()
{
cout << "Enter information for 1st time," << endl;
cout << "Enter minutes: ";
cin >> t1.min;
cout << "Enter seconds: ";
cin >> t1.sec;
cout << "\nEnter information for 2nd time" << endl;
cout << "Enter minutes: ";
cin >> t2.min;
cout << "Enter seconds: ";
cin >> t2.sec;
sum.min = t1.min+t2.min;
sum.sec = t1.sec+t2.sec;
// changing to MINUTES if SECONDS is greater than or equal to 60
if(sum.sec >= 60)
{
++ sum.min;
sum.sec -= 60;
}
cout << endl << "Sum of time = " << sum.min << " minutes " << sum.sec << " seconds";
return 0;
}
using namespace std;
struct TotalTime{
int min;
float sec;
}t1 , t2, sum;
int main()
{
cout << "Enter information for 1st time," << endl;
cout << "Enter minutes: ";
cin >> t1.min;
cout << "Enter seconds: ";
cin >> t1.sec;
cout << "\nEnter information for 2nd time" << endl;
cout << "Enter minutes: ";
cin >> t2.min;
cout << "Enter seconds: ";
cin >> t2.sec;
sum.min = t1.min+t2.min;
sum.sec = t1.sec+t2.sec;
// changing to MINUTES if SECONDS is greater than or equal to 60
if(sum.sec >= 60)
{
++ sum.min;
sum.sec -= 60;
}
cout << endl << "Sum of time = " << sum.min << " minutes " << sum.sec << " seconds";
return 0;
}
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